NEW MAGIC SQUARE METHODS: WHEEL EXPANSION

A Spinning wheel

A Discussion of new Method B Algorithm

To construct a magic square by this method the series 1..n2 is paired up in complementary fashion, for example 1 is paired with n2, 2 with n2-1, etc. These pair of numbers are eventually partitioned into n+1 groups of ½(n-1) pairs including the unpaired middle number of the series. However as opposed to Method A, this partioning is done by choosing triplets of pairs (the numbers and their complements) for the "spoke" numbers and doublets of pairs for the "non-spoke" numbers and filling the entire wheel from the inside out, as shown below.

In other words, a "spoke" is generated from a triplet of pairs for a 3x3 square or a multiple of triplets {a,complement a),(b,complement b),(c,complement c)}... where the equation n - ½(n + 1) gives the number of triplets per nxn square along with the hub.
For example, for a 5x5 square II (below), the two triplets {1,2,3} and {4,5,6} along with their complements {25,24,23} and {22,21,20} are taken from the complementary table below and used to construct the "spokes".

By analysis the number of conformations is equal to the equation {(Σ ¼(n2-4n + 7) - a} × (½(n-1))! where a is varied from 0 to n-1. This method differs from method A in that each group of three pairs may take any available concentric positions on the square. On the other hand, the use of the equation { ¼(n2-4n + 7) × ½ (¼(n2-4n + 7) + 1) × (½ (n-1))!}, avoids having to use summation groups. For a 5x5 square, however, either of these equations generates 12 conformations.

Method B

A magic square is first constructed by filling in the left diagonal with the group of numbers ½ (n2-n+2) to ½(n2+n) using any of the requisite combinations. For a 5x5 square the numbers in the left diagonal are added consecutively for example using variant 1 {11,12,13,14,15} as in square I. The central square is first laid down according to the wheel algorithm, followed by the external second square (as in Square II). The "non-spoke" are finally added according to the parity table on the right.

Square I
11
12 3 24
25 13 1
2 23 14
15
Square II
11 6 21
12 3 24
22 25 13 1 4
2 23 14
5 20 15
   
 
ROWSPAIRPARITY
127O
226E
426E
525O
1 2 3 4 5 6 7 8 9 10 11 12 1 2 3 4 5 6 7 8 9 10 11 12
13 13
25 24 23 22 21 20 19 18 17 16 15 14 25 24 23 22 21 20 19 18 17 16 15 14

The result is Square III and IV, where both square IV and its concentric square are also magic.

Square III
11 19 68 21
    12 3 24    
22 25 13 1 4
2 23 14
57 20 18 15
Square IV
11 19 68 21
10 12 3 24 16
22 25 13 1 4
17 2 23 14 9
57 20 18 15

Alternatively, the "spoke" may be formed by using different combination of numbers. For example the square produced by using {4,5,6} followed by {1,2,3} gives square V then VI which may then be filled in the usual fashion.

Square V
11
12 6 21
22 13 4
5 20 14
15
Square VI
11 3 24
12 6 21
25 22 13 4 1
5 20 14
2 23 15
1 2 3 4 5 6 7 8 9 10 11 12 1 2 3 4 5 6 7 8 9 10 11 12
13 13
25 24 23 22 21 20 19 18 17 16 15 14 25 24 23 22 21 20 19 18 17 16 15 14

One example of a 7x7 spinning magic square

One example (out of 168) of a 7x7 square is the combination 24 → 22 → 27 → 25 → 23 → 28 → 26. The first concentric wheel is produced using for example the first triplet (1-3) along with the last three triplets (22-24) and the central number (25) as shown in square VII. The rest of the "spoke" numbers are added so that the sum of three numbers per row is closest to 75 (the magic sum of a central 7x7 square). Thus between the numbers 1 and 3 the best choice is 1 since the sum produced is 73 as opposed to 71 with the number 3. Repeating for rows one and two using this same method gives square VIII. The "non-spoke" numbers are then filled in according to the following parity table, remembering that the allowable pair sums are n2 = 49, n2+1 = 50 and n2+2 = 51 where these are compared to the possible non-allowed alternatives (note that only half of the parity table is shown since by symmetry the rest of the table is similar):

Row/ColumnNumberPair of SumsParityAllowed
1950+50E+EYes
1751+51O+ONo
2651+51O+OYes
2452+52E+ENo
3347+52O+ENo
3348+51O+ENo
3149+50O+EYes

For example, although line 2 of the parity table contains an allowed O+O, no allowed E+E is available for lines 4-7. Therefore, the allowed line is 1.

Square VII
24
22
27 1 48
47 25 3
2 49 23
28
26
Square VIII
24 9 42
22 6 45
27 1 48
4346 47 25 3 4 7
2 49 23
5 44 28
8 41 26
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25
49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26

We first try filling row three with "non-spoke" numbers. However, placing the sum of allowable pairs 50 and 49 is not as easy as it seems. The first thing to do is to fill in row/column 2 (as shown in square IX) since both pair of numbers are 51. This makes it easier to fill in the rest of the square since row/column three must be filled in with the pair that adds up to 49 (as shown in square X). Note that the number inserted is 31 a reverse H.

Square IX
24 36 9 14 42
40 22 38 6 13 45 11
34 27 1 48 16
4346 47 25 3 4 7
17 2 49 23 33
105 1244 3728 39
815 41 32 26
Square X
24 36 31 9 1914 42
40 22 38 6 13 45 11
2934 27 1 48 16 20
4346 47 25 3 4 7
2117 2 49 23 33 30
105 1244 3728 39
815 1841 3235 26
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25
49 48 47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32 31 30 29 28 27 26

This completes method B. To continue on to brand new Loubère and wheel methods. To go back to the previous Method A-2 or to homepage.


Copyright © 2008 by Eddie N Gutierrez. E-Mail: Fiboguti89@Yahoo.com